0=-17x^2+23x+19

Solution for 0=-17x^2+23x+19 equation:

0=-17x^2+23x+19

We move all terms to the left:

0-(-17x^2+23x+19)=0

We add all the numbers together, and all the variables

-(-17x^2+23x+19)=0

We get rid of parentheses

17x^2-23x-19=0

a = 17; b = -23; c = -19;
Δ = b2-4ac
Δ = -232-4·17·(-19)
Δ = 1821
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-\sqrt{1821}}{2*17}=\frac{23-\sqrt{1821}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+\sqrt{1821}}{2*17}=\frac{23+\sqrt{1821}}{34}
$